The challenge
You are given an array of numbers in which two numbers occur once and the rest occur only twice. Your task is to return the sum of the numbers that occur only once.
For example, repeats([4,5,7,5,4,8]) = 15 because only the numbers 7 and 8 occur once, and their sum is 15. Every other number occurs twice.
The solution in Python code
Option 1:
def repeats(arr):
count = []
for i in arr:
if i not in count:
count.append(i)
else:
count.remove(i)
return sum(count)
Option 2:
def repeats(arr):
return sum([x for x in arr if arr.count(x) == 1])
Option 3:
repeats=lambda a:2*sum(set(a))-sum(a)
Test cases to validate our solution
test.it("Basic tests")
test.assert_equals(repeats([4,5,7,5,4,8]),15)
test.assert_equals(repeats([9, 10, 19, 13, 19, 13]),19)
test.assert_equals(repeats([16, 0, 11, 4, 8, 16, 0, 11]),12)
test.assert_equals(repeats([5, 17, 18, 11, 13, 18, 11, 13]),22)
test.assert_equals(repeats([5, 10, 19, 13, 10, 13]),24)
