## The challenge

Complete the square sum function so that it squares each number passed into it and then sums the results together.

For example, for `[1, 2, 2]` it should return `9` because `1^2 + 2^2 + 2^2 = 9`.

Complete the square sum function so that it squares each number passed into it and then sums the results together.

For example, for `[1, 2, 2]` it should return `9` because `1^2 + 2^2 + 2^2 = 9`.

## The solution in Python

Option 1:

 ``````1 2 3 4 5 `````` ``````def square_sum(numbers): out = [] for i in numbers: out.append(i**2) return sum(out) ``````

Option 2:

 ``````1 2 `````` ``````def square_sum(numbers): return sum(x ** 2 for x in numbers) ``````

Option 3:

 ``````1 2 `````` ``````def square_sum(numbers): return sum(map(lambda x: x**2,numbers)) ``````

## Test cases to validate our solution

 `````` 1 2 3 4 5 6 7 8 9 10 11 12 `````` ``````import test from solution import square_sum @test.describe("Fixed Tests") def basic_tests(): @test.it('Basic Test Cases') def basic_test_cases(): test.assert_equals(square_sum([1,2]), 5) test.assert_equals(square_sum([0, 3, 4, 5]), 50) test.assert_equals(square_sum([]), 0) test.assert_equals(square_sum([-1,-2]), 5) test.assert_equals(square_sum([-1,0,1]), 2) ``````