Square(n) Sum in Python

The challenge

Complete the square sum function so that it squares each number passed into it and then sums the results together.

For example, for [1, 2, 2] it should return 9 because 1^2 + 2^2 + 2^2 = 9.

Complete the square sum function so that it squares each number passed into it and then sums the results together.

For example, for [1, 2, 2] it should return 9 because 1^2 + 2^2 + 2^2 = 9.

The solution in Python

Option 1:

def square_sum(numbers):
    out = []
    for i in numbers:
        out.append(i**2)
    return sum(out)

Option 2:

def square_sum(numbers):
    return sum(x ** 2 for x in numbers)

Option 3:

def square_sum(numbers):
    return sum(map(lambda x: x**2,numbers))

Test cases to validate our solution

import test
from solution import square_sum

@test.describe("Fixed Tests")
def basic_tests():
    @test.it('Basic Test Cases')
    def basic_test_cases():
        test.assert_equals(square_sum([1,2]), 5)
        test.assert_equals(square_sum([0, 3, 4, 5]), 50)
        test.assert_equals(square_sum([]), 0)
        test.assert_equals(square_sum([-1,-2]), 5)
        test.assert_equals(square_sum([-1,0,1]), 2)