The challenge
Create a function that transforms any positive number to a string representing the number in words. The function should work for all numbers between 0 and 999999.
Examples:
number2words(0) ==> "zero"
number2words(1) ==> "one"
number2words(9) ==> "nine"
number2words(10) ==> "ten"
number2words(17) ==> "seventeen"
number2words(20) ==> "twenty"
number2words(21) ==> "twenty-one"
number2words(45) ==> "forty-five"
number2words(80) ==> "eighty"
number2words(99) ==> "ninety-nine"
number2words(100) ==> "one hundred"
number2words(301) ==> "three hundred one"
number2words(799) ==> "seven hundred ninety-nine"
number2words(800) ==> "eight hundred"
number2words(950) ==> "nine hundred fifty"
number2words(1000) ==> "one thousand"
number2words(1002) ==> "one thousand two"
number2words(3051) ==> "three thousand fifty-one"
number2words(7200) ==> "seven thousand two hundred"
number2words(7219) ==> "seven thousand two hundred nineteen"
number2words(8330) ==> "eight thousand three hundred thirty"
number2words(99999) ==> "ninety-nine thousand nine hundred ninety-nine"
number2words(888888) ==> "eight hundred eighty-eight thousand eight hundred eighty-eight"
The solution in Python code
Option 1:
words = "zero one two three four five six seven eight nine" + \
" ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen twenty" + \
" thirty forty fifty sixty seventy eighty ninety"
words = words.split(" ")
def number2words(n):
if n < 20:
return words[n]
elif n < 100:
return words[18 + n // 10] + ('' if n % 10 == 0 else '-' + words[n % 10])
elif n < 1000:
return number2words(n // 100) + " hundred" + (' ' + number2words(n % 100) if n % 100 > 0 else '')
elif n < 1000000:
return number2words(n // 1000) + " thousand" + (' ' + number2words(n % 1000) if n % 1000 > 0 else '')
Option 2:
d={0:'zero',1:'one',2:'two',3:'three',4:'four',5:'five',
6:'six',7:'seven',8:'eight',9:'nine',10:'ten',
11:'eleven',12:'twelve',13:'thirteen',14:'fourteen',15:'fifteen',
16:'sixteen',17:'seventeen',18:'eighteen',19:'nineteen',
20:'twenty',30:'thirty',40:'forty',50:'fifty',
60:'sixty',70:'seventy',80:'eighty',90:'ninety',
100:'hundred',1000:'thousand'}
def number2words(n):
""" works for numbers between 0 and 999999 """
if 0<=n<=20:return d[n]
if 20<n<=99 and n%10:return d[10*(n//10)]+'-'+d[n%10]
if 20<n<99:return d[10*(n//10)]
if n<1000 and n%100==0:return d[n//100]+' '+d[100]
if 100<n<=999:return d[n//100]+' '+d[100]+' '+number2words(n%100)
if n%1000==0:return d[n//1000]+' '+d[1000]
return number2words(n//1000)+' '+d[1000]+' '+number2words(n%1000)
Option 3:
d = {1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five',
6: 'six', 7: 'seven', 8: 'eight', 9: 'nine', 10: 'ten',
11: 'eleven', 12: 'twelve', 13: 'thirteen', 14: 'fourteen',
15: 'fifteen', 16: 'sixteen', 17: 'seventeen', 18: 'eighteen',
19: 'nineteen', 20: 'twenty', 30: 'thirty', 40: 'forty',
50: 'fifty', 60: 'sixty', 70: 'seventy', 80: 'eighty',
90: 'ninety', 0:''}
def number2words(n):
s = (htu(n // 1000) + ' thousand ' if n // 1000 else '') + htu(n % 1000)
return ' '.join(s.split()) if s else 'zero'
def htu(n):
h, tu, u = n//100, n % 100, n % 10
t = (d[tu] if tu in d else d[tu//10*10] + '-' + d[u]).strip('-')
return d[h] + ' hundred ' + t if h else t
Test cases to validate our solution
from solution import number2words
import test
@test.describe("fixed tests")
def _():
@test.it("One digit Tests")
def _():
test.assert_equals(number2words(0), "zero")
test.assert_equals(number2words(1), "one")
test.assert_equals(number2words(8), "eight")
@test.it("Tens Tests")
def _():
test.assert_equals(number2words(10), "ten")
test.assert_equals(number2words(19), "nineteen")
test.assert_equals(number2words(20), "twenty")
test.assert_equals(number2words(22), "twenty-two")
test.assert_equals(number2words(54), "fifty-four")
test.assert_equals(number2words(80), "eighty")
test.assert_equals(number2words(98), "ninety-eight")
@test.it("Hundreds Tests")
def _():
test.assert_equals(number2words(100),"one hundred")
test.assert_equals(number2words(301),"three hundred one")
test.assert_equals(number2words(793),"seven hundred ninety-three")
test.assert_equals(number2words(800),"eight hundred")
test.assert_equals(number2words(650),"six hundred fifty")
@test.it("Thousands Tests")
def _():
test.assert_equals(number2words(1000), "one thousand")
test.assert_equals(number2words(1003), "one thousand three")
