The challenge
Given an array of integers as strings and numbers, return the sum of the array values as if all were numbers.
Return your answer as a number.
The solution in Java code
Option 1 (using stream):
import java.util.List;
public class MixedSum {
public int sum(List<?> mixed) {
return mixed.stream().mapToInt(o -> Integer.parseInt(o.toString())).sum();
}
}
Option 2 (the harder way):
import java.util.List;
public class MixedSum {
public int sum(List<?> mixed) {
int sum = 0;
for (Object element : mixed) {
if (element instanceof Integer) {
sum += (Integer) element;
} else if (element instanceof String) {
sum += Integer.parseInt( (String) element );
}
}
return sum;
}
}
Option 3 (using Objects):
import java.util.List;
public class MixedSum {
public int sum(List<?> mixed) {
int x = 0;
for(Object s: mixed){
x+=Integer.parseInt(s.toString());
}
return x;
}
}
Test cases to validate our solution
import org.junit.Test;
import static org.junit.Assert.assertEquals;
import org.junit.runners.JUnit4;
import java.util.Arrays;
public class SolutionTest {
MixedSum mixedSum = new MixedSum();
@Test
public void test_1() {
assertEquals(10, mixedSum.sum(Arrays.asList(5,"5")));
}
@Test
public void test_2() {
assertEquals(22, mixedSum.sum(Arrays.asList(9, 3, "7", "3")));
}
@Test
public void test_3() {
assertEquals(42, mixedSum.sum(Arrays.asList("5", "0", 9, 3, 2, 1, "9", 6, 7)));
}
@Test
public void test_4() {
assertEquals(41, mixedSum.sum(Arrays.asList("3", 6, 6, 0, "5", 8, 5, "6", 2, "0")));
}
@Test
public void test_5() {
assertEquals(45, mixedSum.sum(Arrays.asList("1", "5", "8", 8, 9, 9, 2, "3")));
}
@Test
public void test_6() {
assertEquals(41, mixedSum.sum(Arrays.asList("3", 6, 6, 0, "5", 8, 5, "6", 2, "0")));
}
@Test
public void test_7() {
assertEquals(61, mixedSum.sum(Arrays.asList(8, 0, 0, 8, 5, 7, 2, 3, 7, 8, 6, 7)));
}
}
