# How to Sort an Integer in Python

Let’s say that you have an integer with value of `9271` and you want to sort it either ascending(`1279`) or descending(`9721`).

How would you do this in Python? How would you sort an integer in either ascending or descending order?

## Sorting our integer

Let’s set our integer to `n`:

``````n = 9271
``````

Now let’s sort it:

``````sorted([i for i in str(n)])

# This will give us a list in ascending order
# ['1', '2', '7', '9']
``````

We can as easily do it the other way:

``````sorted([i for i in str(n)], reverse=True)

# This will give us a list in descending order
# ['9', '7', '2', '1']
``````

## How do we convert our sorted list back to an integer?

``````s = sorted([i for i in str(n)], reverse=True)
int("".join(s))

# 9721
``````

But can we do this in a single line? Yes!

``````descending = int("".join(sorted([i for i in str(n)], reverse=True)))

print(descending)

# 9721
``````

If you just want a quick copy/paste, then you can use these functions to sort an integer in python:

``````def sort_asc(n):
return int("".join(sorted([i for i in str(n)])))

def sort_desc(n):
return int("".join(sorted([i for i in str(n)], reverse=True)))
``````

And here is how to use these functions in how to sort an integer using python:

``````print(sort_asc(473829))
# 234789

print(sort_desc(473829))
# 987432
``````
``````def sort_asc(n):
return int("".join(sorted([i for i in str(n)])))

def sort_desc(n):
return int("".join(sorted([i for i in str(n)], reverse=True)))

print(sort_asc(473829))
# 234789

print(sort_desc(473829))
# 987432
``````