# How to Invite More Women in C

## The challenge

King Arthur and his knights are having a New Years party. Last year Lancelot was jealous of Arthur, because Arthur had a date and Lancelot did not, and they started a duel.

To prevent this from happening again, Arthur wants to make sure that there are at least as many women as men at this year’s party. He gave you a list of integers of all the party goers.

Arthur needs you to return true if he needs to invite more women or false if he is all set.

Input/Output

• `[input]` integer array `L` (`\$a` in PHP)

An array (guaranteed non-associative in PHP) representing the genders of the attendees, where `-1` represents `women` and `1` represents `men`.

`2 <= L.length <= 50`

• `[output]` a boolean value`true` if Arthur need to invite more women, `false` otherwise.

## The solution in C

Option 1:

``````#include <stddef.h>

int invite_more_women(int *arr, size_t count) {
int sum = 0;

for (int i = 0; i < count; ++i) sum += arr[i];

return (sum>0)? 1 : 0;
}
``````

Option 2:

``````#include <stddef.h>

int invite_more_women(int *arr, size_t count) {
int balance = 0;
while (count--)
balance += *arr++;
return balance > 0;
}
``````

Option 3:

``````#include <stdbool.h>
#include <stddef.h>

bool invite_more_women(const int attendee_genders[], size_t count) {
ptrdiff_t sum = 0;
for (size_t i = 0; i < count; i++)
sum += attendee_genders[i];
return sum > 0;
}
``````

## Test cases to validate our solution

``````#include <stdbool.h>
#include <stddef.h>
#include <criterion/criterion.h>

extern void do_test (size_t count, const int array[count], bool expected);

#define ARR_LEN(array) (sizeof(array) / sizeof *(array))

#define sample_test(array, expected) do_test(ARR_LEN(array), array, expected)

Test(tests_suite, sample_tests)
{
sample_test(((int[]){1, -1, 1}), true);
sample_test(((int[]){-1, -1, -1}), false);
sample_test(((int[]){1, -1}), false);
sample_test(((int[]){1, 1, 1}), true);
do_test(0, NULL, false);
}
``````