Given the root
node of a binary search tree, return the sum of values of all nodes with value between L
and R
(inclusive).
The binary search tree is guaranteed to have unique values.
Examples
Example1:
1
2
|
Input: root = [10,5,15,3,7,null,18], L = 7, R = 15
Output: 32
|
Example2:
1
2
|
Input: root = [10,5,15,3,7,13,18,1,null,6], L = 6, R = 10
Output: 23
|
Our solution in Java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
|
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public int rangeSumBST(TreeNode root, int L, int R) {
//output variable
int output = 0;
// Create a stack
Stack<TreeNode> stack = new Stack();
// Add the root node
stack.push(root);
// loop through each element
while (!stack.isEmpty()) {
// remove last item from stack
TreeNode node = stack.pop();
// if the node exists
if (node != null) {
// incrememnt output counts
if (L <= node.val && node.val <= R)
output += node.val;
// push if left
if (L < node.val)
stack.push(node.left);
// push if right
if (node.val < R)
stack.push(node.right);
}
}
// return our count
return output;
}
}
|