The challenge
Given a non-negative integer, return an array / a list of the individual digits in order.
Examples:
123 => [1,2,3]
1 => [1]
8675309 => [8,6,7,5,3,0,9]
The solution in Python code
Option 1:
def digitize(n):
return [int(d) for d in str(n)]
Option 2:
def digitize(n):
return list(map(int, str(n)))
Option 3:
def digitize(n):
lst = []
if n == 0:
return [0]
while n:
n,r = divmod(n,10)
lst.append(r)
lst.reverse()
return lst
Test cases to validate our solution
import test
from solution import digitize
@test.describe("Fixed Tests")
def fixed_tests():
@test.it('Basic Test Cases')
def basic_test_cases():
test.assert_equals(digitize(123), [1,2,3])
test.assert_equals(digitize(1), [1])
test.assert_equals(digitize(0), [0])
test.assert_equals(digitize(1230), [1,2,3, 0])
test.assert_equals(digitize(8675309), [8,6,7,5,3,0,9])
