## The challenge

This function should test if the `factor` is a factor of `base`.

Return `true` if it is a factor or `false` if it is not.

Factors are numbers you can multiply together to get another number.

2 and 3 are factors of 6 because: `2 * 3 = 6`

• You can find a factor by dividing numbers. If the remainder is 0 then the number is a factor.
• You can use the mod operator (`%`) in most languages to check for a remainder

Examples:

2 is not a factor of 7 because: `7 % 2 = 1`

Note: `base` is a non-negative number, `factor` is a positive number.

## The solution in Python

Option 1:

 ``````1 2 `````` ``````def check_for_factor(base, factor): return base/factor == int(base/factor) ``````

Option 2:

 ``````1 2 `````` ``````def check_for_factor(base, factor): return base % factor == 0 ``````

Option 3:

 ``````1 `````` ``````check_for_factor=lambda a,b:not a%b ``````

## Test cases to validate our solution

 `````` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 `````` ``````import test from solution import check_for_factor @test.describe("Fixed Tests") def fixed_tests(): @test.it("Should return True") def should_return_true(): test.assert_equals(check_for_factor(10, 2), True) test.assert_equals(check_for_factor(63, 7), True) test.assert_equals(check_for_factor(2450, 5), True) test.assert_equals(check_for_factor(24612, 3), True) @test.it("Should return False") def should_return_false(): test.assert_equals(check_for_factor(9, 2), False) test.assert_equals(check_for_factor(653, 7), False) test.assert_equals(check_for_factor(2453, 5), False) test.assert_equals(check_for_factor(24617, 3), False) ``````