How to Calculate a Valid Square in Java
The challenge
Given the coordinates of four points in 2D space p1
, p2
, p3
and p4
, return true
if the four points construct a square.
The coordinate of a point p<sub>i</sub>
is represented as [x<sub>i</sub>, y<sub>i</sub>]
. The input is not given in any order.
A valid square has four equal sides with positive length and four equal angles (90-degree angles).
Example 1:
Input: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 = [0,1] Output: true
Example 2:
Input: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 = [0,12] Output: false
Example 3:
Input: p1 = [1,0], p2 = [-1,0], p3 = [0,1], p4 = [0,-1] Output: true
Constraints:
p1.length == p2.length == p3.length == p4.length == 2
-10<sup>4</sup> <= x<sub>i</sub>, y<sub>i</sub> <= 10<sup>4</sup>
The solution in Java code
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