The challenge
Complete the function that takes two integers (a, b, where a < b) and return an array of all integers between the input parameters, including them.
For example:
a = 1
b = 4
//[1, 2, 3, 4]
The solution in Java code
Option 1:
public class Solution {
public static int[] between(int a, int b) {
return java.util.stream.IntStream.rangeClosed(a, b).toArray();
}
}
Option 2:
public class Solution {
public static int[] between(int a, int b) {
int length = 0;
for(int k = a; k <= b; k++){
length++;
}
int[] array = new int[length];
int first = a;
for(int i = 0; i < length; i++){
array[i] = first;
first++;
}
return array;
}
}
Option 3:
public class Solution {
public static int[] between(int a, int b) {
int[] result = new int[b - a + 1];
for (int i = a; i <= b; i++) {
result[i - a] = i;
}
return result;
}
}
Test cases to validate our solution
import org.junit.Test;
import static org.junit.Assert.assertArrayEquals;
import java.util.Random;
public class SolutionTest {
@Test
public void basicTests() {
assertArrayEquals(new int[]{1, 2, 3, 4}, Solution.between(1, 4));
assertArrayEquals(new int[]{-2, -1, 0, 1, 2}, Solution.between(-2, 2));
assertArrayEquals(new int[]{-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10}, Solution.between(-10, 10));
assertArrayEquals(new int[]{5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100}, Solution.between(5, 100));
}
@Test
public void randomTests() {
Random rnd = new Random();
for (int i=0; i<100; ++i) {
int a = rnd.nextInt(201) - 100;
int b = a + rnd.nextInt(new int[]{5,20,50}[rnd.nextInt(3)]) + 1;
int[] expected = java.util.stream.IntStream.rangeClosed(a, b).toArray();
int[] actual = Solution.between(a, b);
assertArrayEquals(expected, actual);
}
}
}
